java怎么根据xml模板生成xml文件

在Java中，可以使用DOM（Document Object Model）或者JAXB（Java Architecture for XML Binding）来生成XML文件。

使用DOM:

import javax.xml.parsers.DocumentBuilder;import javax.xml.parsers.DocumentBuilderFactory;import javax.xml.transform.Transformer;import javax.xml.transform.TransformerFactory;import javax.xml.transform.dom.DOMSource;import javax.xml.transform.stream.StreamResult;import org.w3c.dom.Document;import org.w3c.dom.Element;public class GenerateXML {public static void main(String[] args) {try {DocumentBuilderFactory documentFactory = DocumentBuilderFactory.newInstance();DocumentBuilder documentBuilder = documentFactory.newDocumentBuilder();Document document = documentBuilder.newDocument();Element rootElement = document.createElement("root");document.appendChild(rootElement);Element childElement = document.createElement("child");childElement.appendChild(document.createTextNode("Hello World"));rootElement.appendChild(childElement);TransformerFactory transformerFactory = TransformerFactory.newInstance();Transformer transformer = transformerFactory.newTransformer();DOMSource source = new DOMSource(document);StreamResult result = new StreamResult(new File("output.xml"));transformer.transform(source, result);System.out.println("XML file generated successfully!");} catch (Exception e) {e.printStackTrace();}}}

使用JAXB:

import java.io.File;import javax.xml.bind.JAXBContext;import javax.xml.bind.JAXBException;import javax.xml.bind.Marshaller;public class GenerateXML {public static void main(String[] args) {try {JAXBContext jaxbContext = JAXBContext.newInstance(YourClass.class);Marshaller marshaller = jaxbContext.createMarshaller();marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);YourClass object = new YourClass(); // create an object of your classmarshaller.marshal(object, new File("output.xml"));System.out.println("XML file generated successfully!");} catch (JAXBException e) {e.printStackTrace();}}}

以上代码示例分别使用DOM和JAXB来生成XML文件，你可以根据自己的需求选择其中一种方式实现。

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